in fig.,ABCD is a rectangle.if angle OAB = 28 find angle OBC. also AC and BD intersect at O

Asked by  | 20th Jul, 2008, 12:12: AM

Expert Answer:

in   rectangle ABCD ,  angle OAB = 28   given 

  AC and BD intersect at O

 therefore   OAB is an isoceles triangle    ...  [  since the diagonals are congruent and bisect  each other in rectangle ]

  then angle  OAB =  angleOBA 

 We know that  angle ABC = 90

 so    angle  OBC  = angle  ABC  - angle OBA  ==> 90 - 28  == 62

 angle  OBC == 62 degrees

Answered by  | 24th Jul, 2008, 09:01: AM

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