If there is a quadrilateral ABCD, prove that AB+BC+CD+DA>2(AC+BD)
Asked by | 12th Jan, 2009, 11:56: AM
Expert Answer:
To prove:
AB+BC+CD+DA > AC+BD
Solution:
2 (AB+BC+CD+DA) = (AB+BC) + (AD+AB) + (AD+CD) + (CD+BC)
> AC + BD+AC+BD
> 2 (AC+BD)
Answered by | 13th Jan, 2009, 03:09: PM
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