If there is a quadrilateral ABCD, prove that AB+BC+CD+DA>2(AC+BD)

Asked by  | 12th Jan, 2009, 11:56: AM

Expert Answer:

To prove:

AB+BC+CD+DA > AC+BD

Solution:

2 (AB+BC+CD+DA) = (AB+BC) + (AD+AB) + (AD+CD) + (CD+BC)

                                   > AC + BD+AC+BD

                                  > 2 (AC+BD)

Answered by  | 13th Jan, 2009, 03:09: PM

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