Find zeroes of polynomial 

(a)x2+2root2-6

(b)4root3x2+5x-2root3

(c)2x2-3+5x

(d)x2-(root3-1)x+root3

 

Asked by Abhinav050806 | 5th May, 2018, 07:42: PM

Expert Answer:

x2 + 2√2 x - 6 
= x2 + 3√2 x - √2 x - 6                      (3√2 - √2 = 2√2 and 3√2 × √2 = 6)
= x (x + 3√2) - √2 (x + 3√2)
= (x + 3√2) (x - √2) 

Answered by Sneha shidid | 7th May, 2018, 01:06: PM