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CBSE Class 9 Answered

find the value of open parentheses cube root of 8 close parentheses to the power of negative 1 divided by 2 end exponent open parentheses square root of 4 close parentheses to the power of negative 7 end exponent cross times open parentheses square root of 2 close parentheses to the power of negative 5 end exponent
Asked by arunkumarsingh0004 | 17 Apr, 2019, 12:18: PM
answered-by-expert Expert Answer
begin mathsize 16px style open parentheses cube root of 8 close parentheses to the power of fraction numerator negative 1 over denominator 2 end fraction end exponent equals open parentheses cube root of 2 cubed end root close parentheses to the power of fraction numerator negative 1 over denominator 2 end fraction end exponent equals open parentheses 2 cubed close parentheses to the power of 1 third cross times fraction numerator negative 1 over denominator 2 end fraction end exponent equals 2 to the power of fraction numerator negative 1 over denominator 2 end fraction end exponent equals fraction numerator 1 over denominator square root of 2 end fraction end style
Answered by Sneha shidid | 17 Apr, 2019, 02:04: PM
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