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Derivations of equations of motion
Asked by Jaypan14 | 07 Jul, 2018, 06:08: PM
Equation of motion 1.  :-     v = u+a×t

where u and v are initial and final velocity respectively. acceleration is a and t is time taken by the object to change velocity from u to v.

Acceleration is defined as rate of change of velocity.

hence,    a = (v-u)/t  or v = u+a×t

Equation of motion 2,    S = u×t + (1/2)×a×t2

where S is the ditance travelled in t seconds with initial velocity u and acceleration a

Distance travelled  S = average velocity × time =
let us substitute, v = u+a×t in eqn.(1),  then we have,   S =
Equation. 3     v2 = u2 + 2×a×S

eqn.(1) is rewritten here
Distance travelled  S = average velocity × time =
let us substitute t using equation of motion (1),  t =(v-u)/a in the above eqn.(1)

the we have,

Answered by Thiyagarajan K | 07 Jul, 2018, 06:31: PM

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