ICSE Class 9 Answered
Derivations of equations of motion
Asked by Jaypan14 | 07 Jul, 2018, 06:08: PM
Expert Answer
Equation of motion 1. :- v = u+a×t
where u and v are initial and final velocity respectively. acceleration is a and t is time taken by the object to change velocity from u to v.
Acceleration is defined as rate of change of velocity.
hence, a = (v-u)/t or v = u+a×t
Equation of motion 2, S = u×t + (1/2)×a×t2
where S is the ditance travelled in t seconds with initial velocity u and acceleration a
Distance travelled S = average velocity × time =
let us substitute, v = u+a×t in eqn.(1), then we have, S =
Equation. 3 v2 = u2 + 2×a×S
eqn.(1) is rewritten here
Distance travelled S = average velocity × time =
let us substitute t using equation of motion (1), t =(v-u)/a in the above eqn.(1)
the we have,
Answered by Thiyagarajan K | 07 Jul, 2018, 06:31: PM
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