AD is the median of triangle ABC and M is the mid point of AD. also BM produced meets AC at N . Prove that AN=1/3 AC.
Asked by sanya wason | 9th Feb, 2011, 04:10: PM
Here is the solution:
Through D, Draw DK||BN.
In triangleADK, M is the mid-point of AD and MN||DK.
Therefore, N is the mid-point of AK.
In triangleBCN, D is the mid-point of BC and BN||DK.
Therefore, K is the mid-point of NC.
From (i) and (ii),
Answered by | 11th Feb, 2011, 10:18: AM
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