ABCD is Rhombus,EABF is a straight line such that EA=AB=BF.Prove that ED and FC when produced meet at Right Angle
Asked by topper1996 | 11th Oct, 2010, 06:36: AM
Expert Answer:
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Here is the solution of your question
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Dear Student
Here is the solution of your question
DearHope it clarifies your doubt
Regards
Team Topperlearning
Answered by | 20th Oct, 2010, 04:06: PM
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