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ICSE Class 9 Answered

A train is moving with a velocity of 90 km/h when the brakes are applied.The retardation produced is 0.5 m/s2.Find: (1) velocity after 10 s ? (2) time taken by train to come to rest ?
Asked by Vikas | 23 May, 2018, 12:24: AM
answered-by-expert Expert Answer
Equation to be applied  " v = u - a×t ", v is final velocity, u is initial velocity, a is retardation and t is time.
 
Velocity at the time of applying break = 90 km/h  = 90 km/h × (5/18) = 25 m/s 
 
(1) velocity after 10 s :-   v = 25-(1/2)×10 = 20 m/s
 
(2) time to come to rest :-  0 = 25-(1/2)×t  , solving for t ,  we get  t = 50 s
Answered by Thiyagarajan K | 23 May, 2018, 11:00: AM
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