ICSE Class 9 Answered
A cyclist driving at 36 km/h stops in 2s by the application of brakes.Calculate : (1) retardation (2) distance covered during application of brakes ?
Asked by Vikas | 23 May, 2018, 00:20: AM
Equations are to be applied is "v = u - a×t " and "S = u×t - (1/2)×a×t2 "
v is final velocity, u initial velocity, a is retardation, S is distance travelled and t is time.
initial velocity = 36 km/h ×(5/18) = 10 m/s
(1) retardation :- 0 = 10-a×2 , solving for a we get retardation a = 5 m/s2
(2) distance :- S = 10×2 -(1/2)×5×4 = 10 m
Answered by Thiyagarajan K | 23 May, 2018, 11:14: AM
Application Videos
Concept Videos
ICSE 9 - Physics
Asked by pinaloswal1 | 13 Jul, 2024, 19:03: PM
ICSE 9 - Physics
Asked by 2016159 | 12 Jul, 2024, 16:20: PM
ICSE 9 - Physics
Asked by 2016159 | 26 Jun, 2024, 19:13: PM
ICSE 9 - Physics
Asked by 2016159 | 13 Jun, 2024, 23:23: PM
ICSE 9 - Physics
Asked by naitikv632009 | 03 Jun, 2024, 07:20: AM
ICSE 9 - Physics
Asked by 2016159 | 29 May, 2024, 19:50: PM
ICSE 9 - Physics
Asked by 2016159 | 29 May, 2024, 19:48: PM
ICSE 9 - Physics
Asked by modhukuruvenkateshwarlu | 13 Apr, 2024, 15:03: PM
ICSE 9 - Physics
Asked by thesangeeta1990 | 08 Mar, 2024, 16:37: PM