A car starting from rest acquires a velocity of 36 km/h in 5 s. Calculate: (1) its accleration (2) distance covered by it ?

Asked by nisha_vini29 | 22nd May, 2018, 11:12: PM

Expert Answer:

acceleration = (v-u) / t ;
 
v = final speed = 36 km/h = 36×(5/18) = 10 m/s; u is initial spped , u = 0; t is time and  t = 5 s;
 
acceleration = 10/5 = 2 m/s2
 
distance S = u×t + (1/2)×a×t2 = (1/2)×2×5×5 = 25 m

Answered by Thiyagarajan K | 23rd May, 2018, 02:56: PM

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