(6-2y+4z)square

Asked by singhjayant849 | 28th Mar, 2019, 11:21: AM

Expert Answer:

Using (a + b + c)2 = a2 + b2 + c + 2ab + 2bc + 2ac
→(6-2y+4z)2 = (6)2 + (-2y)2 + (4z) + 2(6)(-2y) + 2(-2y)(4z) + 2(6)(4z)
                    = 36 + 4y2 + 16z2 - 24y - 16yz + 48z

Answered by Yasmeen Khan | 28th Mar, 2019, 05:12: PM