(6-2y+4z)square
Asked by singhjayant849
| 28th Mar, 2019,
11:21: AM
Expert Answer:
Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac
→(6-2y+4z)2 = (6)2 + (-2y)2 + (4z)2 + 2(6)(-2y) + 2(-2y)(4z) + 2(6)(4z)
= 36 + 4y2 + 16z2 - 24y - 16yz + 48z
Answered by Yasmeen Khan
| 28th Mar, 2019,
05:12: PM
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