1.diagonals of a parallelogram ABCD intersect at O. if angleBOC=90 degree and angleBDC=40 degree,then find angleOAB.

Asked by  | 2nd Dec, 2012, 07:08: PM

Expert Answer:

 
Angle AOB=180-AngleBOC=180-90=90
AngleDBA=AngleBDC=40
in triangleOAB
AngleOAB=180-(AngleAOB+AngleOBA)=180-(90+40)=50
 
therfor Angle OAB=50 degree

Answered by  | 3rd Dec, 2012, 11:17: PM

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