Question
Tue September 06, 2011 By: Sarika Vijay Kumar

The Fourth term of an A.P. is ten times the first. Prove that the sixth term is four times the second term.

Expert Reply
Tue September 06, 2011
The formula for nth term of an A.p is a+(n-1)d,where a is the first term,d is the common difference.
Given,4th term=10 a.
=>10a=a+(4-1)d--(1)
=>9a=3d
=>d=3a---(2)
now,sixth term=a+(6-1)d
=>a+5d
=>a+5(3a)=16a
Thus,sixth term=4(4a)=4(2nd term)
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