Question
Thu October 25, 2012 By: Jay Acharya

if the cell potential at 298 k in 0.096 V.if the ph of solution is 1.396, then caculate concentration of sn2+.

Expert Reply
Tue April 23, 2013
We know that
pH=-log[H+]
1.396=-log[H+]
[H+]=antilog 1.396
[H+]=24.886
 
E=Eo-0.0591/2 log [Sn+2]/[H+]
0.096=0.14-0.0591/2 log [Sn+2]/[24.886]2
Solving this equation we can get the value of [Sn+2]
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