Question
Tue May 22, 2012 By: Shourya Mukherjee

A body is dropped from a height of 2m. It penetrates into the sand on the ground through a distance of 10cm before coming to rest. What is the retardation of the body in the sand? Please explain clearly.

Expert Reply
Wed May 23, 2012
When the body drops from height 2m & will reach the ground, its  u = 0 
v = ?
 
v2 - u2 = 2gh
 
v2 = 2 * 9.8 * 2 = 4 * 9.8
 
 
Now, this v is the initial velocity for calculation retardation
And final velocity is zero
 
And distnace s = 10 cm
 
from the formula  v2 - u2 = 2as
 
a = v2-u2 /2s
 
a = -196 m/s2
 
 
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