Question
Tue June 12, 2012 By: Meenakshi

If the zeroes of the polynomial x3-3x2+x+1 are a-b, a, a+b. Find a and b.

Expert Reply
Wed June 13, 2012
Sum of zeroes = a - b + a + a + b = 3a = -(-3)/1 = 3
This gives a = 1
 
Product of zeroes = a(a2 - b2) = -1/1 = -1
1(1 - b2) = -1
b2 = 2
b = square root (2), -square root (2)
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