Question
Sun June 24, 2012 By: Soma
 

if 1 is a zero of the polynomial p[x]=ax^2-3[a-1]x-1,then how to find the value of a?

Expert Reply
Sun June 24, 2012
Given, 1 is the zero of ax2-3[a-1]x-1.
Therefore,
a(1)2-3[a-1](1)-1 = 0
a - 3(a - 1) - 1 = 0
a - 3a + 3 - 1 = 0
-2a + 2 = 0
2a = 2
a = 1
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