Question
Sun April 29, 2012 By:

I have had problems in balancing the following equations, can you please help me out?

Expert Reply
Mon April 30, 2012
Fe2(SO4)3 + 6 NH3 + 6 H2O ---> 2 Fe(OH)3 + 3 (NH4)2SO4
 
 



 
5 P4 + 80 HNO3 = 20 H3PO4 + 80 NO2 + H20
 
 
Cu  +  2HNO3       --->  Cu(NO3)2  +  H2
2HNO3   --->  H2O +  N2O5
N2O5 + 3H-----> 3H2O+ 2NO

3Cu+ 8HNO3----> 3Cu(NO3)2 + 2NO +4H2O
 
 
 
4 Zn + 10 HNO3 = 4 Zn(NO3)2 + NH4NO3 + 3 H2O
 
 
 
 
I2 + 6H2O ----> 2IO3- + 12H+  + 10e-
NO3- + 2H+ + e- ----> NO2H2O

Multiply the second equation by ten, and add them together:

I2 + 6 H2O ---> 2IO3- + 12H+ + 10e-
10NO3- + 20H+ + 10e- ----> 10NO2 + 10H2O
==================================
I2 + 10NO3- + 8H+ ----> 2 IO3- + 10NO2 + 4H2O

Add two H+ to both sides to neutralize the NO3- and IO3 -, and you get

I2 + 10HNO3 -----> 2HIO3 + 10NO2 + 4H2O

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