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Tue October 21, 2014  

Ans: left parenthesis i right parenthesis space fraction numerator 3 cross times 27 to the power of n plus 1 end exponent plus 9 cross times 3 to the power of 3 n minus 1 end exponent over denominator 8 cross times 3 to the power of 3 n minus 5 end exponent plus 27 to the power of n end fraction equals fraction numerator 3 cross times 27 to the power of n cross times 27 plus 9 cross times begin display style 27 to the power of n over 3 end style over denominator 8 cross times begin display style 27 to the power of n over 243 end style plus 27 to the power of n end fraction equals fraction numerator 3 cross times 27 plus begin display style 3 end style over denominator begin display style 8 over 243 end style plus 1 end fraction equals fraction numerator 84 cross times 243 over denominator 251 end fraction  left parenthesis i i right parenthesis space P l e a s e space r e p o s t space t h e space s e c o n d space q u e s t i o n space c o r r e c t l y.

Tue October 21, 2014  

Ans: L e t space t h e space s h a r e space o f space R i t a space b e space x. therefore S h a r e space o f space S e e m a space equals 500 minus x 1 third space s h a r e space o f space R i t a equals 1 half s h a r e space o f space S e e m a rightwards double arrow 1 third x equals 1 half left parenthesis 500 minus x right parenthesis rightwards double arrow x over 3 equals 250 minus x over 2 rightwards double arrow x over 3 plus x over 2 equals 250 rightwards double arrow fraction numerator 5 x over denominator 6 end fraction equals 250 rightwards double arrow x equals fraction numerator 250 cross times 6 over denominator 5 end fraction therefore x equals 300 S h a r e space o f space R i t a space equals R s. space 300 S h a r e space o f space S e e m a space equals R s. space 200

Mon October 20, 2014  

Ans: Angular momentum of a body about a given axis is the product of linear momentum and the perpendicular distance of line of action of linear momentum vector from the axis of rotataion. This is the physical meaning of angular momentum .  i.e Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. Angular momentum is a vector quantity.  Geometrical meaning of angular momentum . 
 

   

Mon October 20, 2014  

Ans: 2 square root of 2 x plus 1 end root minus 2 x equals 1 rightwards double arrow 2 square root of 2 x plus 1 end root equals 1 plus 2 x rightwards double arrow 4 left parenthesis 2 x plus 1 right parenthesis equals left parenthesis 1 plus 2 x right parenthesis squared space left square bracket S q u a r i n g space b o t h space s i d e s right square bracket rightwards double arrow 8 x plus 4 equals 4 x squared plus 4 x plus 1 rightwards double arrow 4 x squared minus 4 x minus 3 equals 0 rightwards double arrow 4 x squared minus 6 x plus 2 x minus 3 equals 0 rightwards double arrow 2 x left parenthesis 2 x minus 3 right parenthesis plus 1 left parenthesis 2 x minus 3 right parenthesis equals 0 rightwards double arrow left parenthesis 2 x minus 3 right parenthesis left parenthesis 2 x plus 1 right parenthesis equals 0 x equals 3 over 2 comma minus 1 half

Mon October 20, 2014  

Ans: square root of 2 x squared minus 2 x plus 1 end root minus 2 x plus 3 equals 0 rightwards double arrow square root of 2 x squared minus 2 x plus 1 end root equals 2 x minus 3 rightwards double arrow 2 x squared minus 2 x plus 1 equals open parentheses 2 x minus 3 close parentheses squared space left square bracket S q u a r i n g space b o t h space s i d e s right square bracket rightwards double arrow 2 x squared minus 2 x plus 1 equals 4 x squared minus 12 x plus 9 rightwards double arrow 0 equals 2 x squared minus 10 x plus 8 rightwards double arrow x squared minus 5 x plus 4 equals 0 rightwards double arrow x squared minus 4 x minus x plus 4 equals 0 rightwards double arrow x left parenthesis x minus 4 right parenthesis minus 1 left parenthesis x minus 4 right parenthesis equals 0 rightwards double arrow left parenthesis x minus 1 right parenthesis left parenthesis x minus 4 right parenthesis equals 0 therefore x equals 1 comma 4

Mon October 20, 2014  

Ans: Rabies is a viral disease that causes acute inflammation of the brain in humans and other warm blooded animals. Rabies is mostly transmitted to humans and between animals through the saliva of infected animals. Transmission is generally through a bite from any infected animal. After a typical human infection by the bite of a dog, the virus enters the peripheral nervous system. It then travels along the nerves towards the central nervous system. Once the virus reaches the brain, it rapidly causes encephalitis and symptoms appear. Rabies may also inflame the spinal cord producing myelitis.

Sun October 19, 2014  

Ans: The nth term is the general term of a series. a n  stands for nth term of the series. 'N' stands for the no. of terms. For eg: Suppose for a series:1,4,7,10,........ Here (first term)a=1,(common difference)d=3 The general term / nth term of this series is t n  =a+(n-1)d =1+(n-1)3 =1+3n-3 =3n-2 This term t n  denotes the general term of the series. If you put n=3, in this term you get t 3  = 3×3-2=7, which is the third term in the series. The same principle applies to any series. Hope your doubt is cleared.

Sun October 19, 2014  

Ans: Given:  Mass of the wooden block, m= 8kg  Relative density of wood = 0.8 We know that:  begin mathsize 14px style fraction numerator Density space of space wood over denominator Density space of space water end fraction equals Relative space density space of space wood fraction numerator Density space of space wood over denominator Density space of space water end fraction equals 0.8 Density space of space wood space equals space 0.8 space cross times Density space of space water Density space of space wood space equals space 0.8 space cross times 1000 space Kg divided by straight m cubed end style   The upthrust experienced by the wooden block upward will be balanced by the weight of the wooden block acting downwards + the tension on the string i.e. Upthrust = Weight + Tension Therefore the tension on the string = Upthrust - Weight The upthrust experienced by the wooden block = Volume of water displaced by the block × Density of water × g   begin mathsize 14px style Volume space of space water space displaced space by space the space block space equals fraction numerator Mass space of space the space wood space block over denominator Density space of space wood space end fraction straight V space equals fraction numerator 8 over denominator 0.8 cross times 1000 end fraction end style   begin mathsize 14px style Upthrust space equals space fraction numerator 8 over denominator 0.8 cross times 1000 end fraction cross times space 1000 space cross times space 10 space space space space space space space space space space space space space space space equals 100 space straight N end style   Tension on the string = Upthrust - Weight                               = 100 N - (8 ×10) N                               =20 N Therefore Tension on the sring = 20N

Sun October 19, 2014  

Ans: Given mass of the metal piece, m = 160 g = 0.160 kg Density of metal = 8000 kg/m 3 Here we can say that the weight of the metal piece = buoyant force(F B ) + Normal force i.e. weight of the metal piece= mg Buoyant force, F B  = Volume of water displaced by metal ×ρ water x g mg = F B  + Normal force   begin mathsize 14px style Normal space force space equals space mg minus space straight F subscript straight B space space space space space space space space space space space space space space space space space space space space space equals space straight m cross times straight g space minus straight V cross times straight rho subscript water cross times straight g Volume space of space water space displaced space by space metal comma space straight V space equals straight m over straight rho subscript metal equals fraction numerator 0.160 over denominator 8000 end fraction equals 0.00002 Normal space force space equals open parentheses space 0.160 cross times 9.8 close parentheses space minus space open parentheses 0.00002 cross times 1000 cross times 9.8 close parentheses space space space space space space space space space space space space space space space space space space space space space equals 1.568 space minus 0.196 space space space space space space space space space space space space space space space space space space space space space equals 1.372 space straight N space space space space space space space space space space space space space space space space space space space space space equals 1.4 space straight N space space space space space space space space space space space space space space space space space space space end style                               

Sun October 19, 2014  

Ans: begin mathsize 14px style The space block space will space float space in space mercury space if space its space weight space is space equal space to space the space weight space of space mercury space displaced space by space it. Density space of space iron comma space straight rho subscript straight i equals 7.2 space straight g divided by cm cubed Density space of space mercury comma space straight rho subscript straight m equals 13.6 space straight g divided by cm cubed Length space of space each space side space of space the space iron space block equals 10 space cm Let space straight x space be space the space height space of space the space block space above space the space mercury space level space in space the space vessel. space Then comma space the space volume space of space the space block space inside space the space mercury space is comma straight V subscript straight m equals 10 space cross times space 10 space cross times space left parenthesis 10 minus straight x right parenthesis This space is space also space equal space to space the space volume space of space mercury space displaced space by space the space block. Weight space of space this space volume space of space mercury space is comma space straight W equals straight V subscript straight m straight rho subscript straight m straight g space equals space straight V subscript straight m space cross times space 13.6 space cross times space 981 space equals space upthrust space on space block Total space volume space of space the space iron space block space is comma straight V equals space 10 space cross times space 10 space cross times space 10 space equals space 1000 space cm cubed Hence comma space its space weight space is comma straight W equals Vρ subscript straight i straight g equals straight V space cross times space 7.2 space cross times space 981 The space iron space block space floats comma space therefore comma space Weight space of space mercury space displaced equals Weight space of space the space iron space block 100 space cross times space left parenthesis 10 minus straight x right parenthesis space cross times space 13.6 space cross times space 981 equals 1000 space cross times space 7.2 space cross times space 981 100 space cross times space left parenthesis 10 minus straight x right parenthesis space cross times space 13.6 space equals 1000 space cross times space 7.2 left parenthesis 10 minus straight x right parenthesis space cross times space 1360 space equals space 7200 10 minus straight x equals 7200 over 1360 10 minus straight x equals 5.29 10 minus 5.29 equals straight h straight x equals 4.71 So space the space height space of space the space block space above space mercury space level equals 4.71 space cm end style

Sun October 19, 2014  

Ans: begin mathsize 14px style mass space of space brass space in space air equals 12.9 space straight g mass space of space barss space in space water equals 11.3 space straight g mass space of space water space displaced equals 13.9 minus 11.3 equals 1.6 space straight g relative space density space of space copper equals 8.9 relative space density space of space zinc equals 7.1  Relative space density equals fraction numerator density space of space substance over denominator density space of space water end fraction rightwards double arrow Density space of space copper equals 8.1 space straight g divided by cc which space can space be space written space as space Mass over volume equals 8.1 space straight g divided by cc simillarly space Density space of space zinc equals 7.9 space straight g divided by cc and space volume space of space alloy equals 1.6 space cc Let space straight x space be space the space mass space of space copper space in space alloy hence comma space alloy space contains space the space substances space Volume space of space alloy equals Voume space of space copper plus Volume space of space zinc 1.6 equals fraction numerator straight x over denominator 8.9 end fraction plus fraction numerator 12.9 minus straight x over denominator 7.1 end fraction 1.6 equals 7.1 straight x plus 8.9 left parenthesis 12.9 minus straight x right parenthesis straight x equals 7.614 space straight g Mass space of space copper space is space 7.614 space straight g.    end style

Sun October 19, 2014  

Ans: By the principle of floatation,   begin mathsize 14px style fraction numerator Volume space of space iceberg space immersed over denominator Total space volume space of space iceberg end fraction equals fraction numerator Density space of space ice over denominator Density space of space sea space water end fraction Given space density space of space ice space equals space 917 space kg space divided by straight m cubed comma space Density space of space sea space water space equals space 1025 space kg space divided by straight m cubed fraction numerator Volume space of space iceberg space immersed over denominator Total space volume space of space iceberg end fraction equals fraction numerator 917 space kg space divided by straight m cubed over denominator 1025 space kg space divided by straight m cubed end fraction space space space equals 0.89 Thus space 0.89 to the power of th space part space of space volume space of space iceberg space will space remain space beneath space the space water space surface. space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space end style

Sun October 19, 2014  

Ans: Dear Shreyash.98rana@gmail.com

Thanks for asking us a question in Ask the Expert section of TopperLearning.com.
In case of multiple questions within a query, please post each question individually and let us know where you are getting stuck so that we would be able to explain things better.     Solution of your first query,   1-methyl propane is nothing but n-butane which is a structural isomer of C 4 H 10 (butane).   The isomers of C 4 H 10 (butane) are as follows: n-butane and 2-methyl propane.   Regards

Topperlearning Team.

Sat October 18, 2014  

Ans: Transpiration in tall trees occurs through lenticel because it occurs in woody stems.

Sat October 18, 2014  

Ans: The value of angle is a scalar quantity, and hence, is a magnitude.   So, the value of tan α has to modulus of B over modulus of A, i.e.   begin mathsize 14px style tanα equals fraction numerator open vertical bar straight B with rightwards arrow on top close vertical bar over denominator open vertical bar straight A with rightwards arrow on top close vertical bar end fraction equals straight B over straight A end style

Sat October 18, 2014  

Ans: Dear akanshapari4@gmail.com

Thanks for asking us a question in Ask the Expert section of TopperLearning.com.
The scope of this helpdesk is to answer subject related queries which are relevant to understanding concepts and solving problems. Hence we regret that we would not be able to answer your query.

Regards

Topperlearning Team.

Sat October 18, 2014  

Ans: Difference between monocotyledonous root and monocotyledonous stem: Anatomical part Monocotyledonous root Monocotyledonous stem Epidermis Cells are thin walled, tightly placed and uncutinised. Many epidermal cells protrude out in the form of unicellular root hairs. Thus this layer is also called piliferous layer. Cells are parenchymatous, tightly placed and cutinised and devoid of chloroplast. Epidermal layer bears stomata. This layer is without any appendages such as trichomes. Cortex Cells are parenchymatous, thin walled and enclose intercellular spaces. Cortical cells store food. The cells also conduct water from epidermis to inner tissues. It is 2-3 layers thick and collenchymatous. It provides mechanical strength to the stem. Endodermis Single layered endodermis is present which consists of barrel shaped, closely packed cells without any intercellular spaces. Endodermis is absent. Pericycle Pericycle is single layered and lies on the inner side of the endodermis. Pericycle is absent. Vascular Bundles More than 6 vascular bundles are present. Xylem and phloem bundles alternate each other. Protoxylem lies in contact with the pericycle. Metaxylem is present towards the centre of the root. A parenchyamtous tissue lies between xylem and phloem called conjuctive tissue. Conjuctive tissue does not form the vascular cambium. Vascular bundles are large in number. There are many vascular bundles scattered. Each bundle is surrounded by the sclerenchymatous bundle sheath. They are of conjoint and closed type. The bundles are large towards the centre and small towards the periphery. Phloem parenchyma is absent. Cavities filled with water called schizolysigenous water canal or cavity. Pith The pith is well developed. Cells are parenchymatous with intercellular spaces. Pith cells store food. Pith is absent. Ground tissue Lacks ground tissue. Monocot stem does not show any distinction in general cortex, endodermis, pericycle and pith. It is parenchymatous and occupies the entire stem from interior.

Sat October 18, 2014  

Ans: Dear shahnaj.34@gmail.com

You can only view the topper learning videos. There is no provision  for downloading those videos.
Regards

Topperlearning Team.

Sat October 18, 2014  

Ans: The popular struggles and movements in Nepal and Bolivia took place at different times in different contexts. Though the movements had many similarities, it had some main differences too. These were: The movement in Nepal took place to establish democracy, while the struggle in Bolivia reflected people’s expectations of the elected democratic government. The popular struggle in Bolivia was about one specific unpopular decision taken by the government (privatization of water supply), while the struggle in Nepal was about changing the foundations of the country (monarchy to democracy) and its politics. The struggles of both the countries were successful; however their impact was felt at different levels.

Sat October 18, 2014  

Ans: Two stages of democratic movement in Nepal were: 1990-96 Until 1990, Nepal was a constitutional monarchy and the king had all the major powers. As people protested against the monarchial rule, King Birendra, agreed to large scale political reforms resulting in the creation of the parliamentary monarchy. The king remained as the head of the state while, the Prime Minister was declared as the head of the government. The first free and fair elections were held in Nepal in 1991 and the Nepali Congress registered its victory. 2005-07 In 2001, the king of Nepal was killed and the new king Gynandra took advantage of internal conflicts that were taking place in Nepal. In Feb. 2005, the king dissolved the Parliament and dismissed the Prime Minister and assumed all powers into his hands. This sparked protests by the people of Nepal who demanded restoration of democracy. They were also joined by the Maoist insurgents and various other organisations. The struggle for democracy continued and finally the king had to bow down. The Parliament and the interim government were formed and they passed many laws which greatly curtailed the powers of the king. This struggle came to be known as Nepal’s second movement for democracy
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