Tue March 13, 2012 By:

A boy pushes a 5.00 kg cart in a circle, starting at 0.500 m/s and accelerating to 3.00 m/s. How much work was done on the cart?

Expert Reply
Wed March 14, 2012
Work done, W by the boy on the cart = increase of kinetic energy of the cart. So W is given by
W = 0.5*5.00*[3.00^2 - 0.500^2] = 21.875 J or 21.9 J. Boy in addition will have to work against friction too
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