Why in vertical motion of pulley T=m1g-m2a?
Asked by
18th December 2011,
12:00 AM
Answered by Expert
Answer:
here m1 is going up and m2 is going down with accl a.so net force on m1 is in upward dir and net force on m2 is in downward dir.
T is the tension in the string.
for m2:the net force is in downward direction ie net accleration a in downward dir ie net force is m2a. . at a time, in m2, two forces are acting, weight in downward dir and tension of the string in upward.so this net force is m2g-T.
so, m2g-T=m2a
for m1:similarly:
T-m1g=m1a
if you solve these equation you can get T.
but T =m2g-m2a
or T=m1g+m1a
this comes from net force concept.
Answered by Expert
19th December 2011,
10:37 AM
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