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what kind of sums would come in neet for topic BALANCING REACTIONS BY OXIDATION METHOD, where you have to add,water and h2 molecules, etc?

I dnt know how would they frame query.

give me examples for that kind of sums with solutions please.

Asked by imtiyazmulla68 11th April 2018, 7:41 PM
Answered by Expert
Answer:
 
 

1)    Oxidation Number Method

·         The composition and formulae must be known for the reactants and products while writing equations for oxidation–reduction reactions.

·         The following steps need to be used for balancing the equations.

 
  Rounded Rectangle: Step 1

 

 

 


·         Write the net unbalanced equation with the correct formula for each reactant and product.

 
  Rounded Rectangle: Step 2

 

 

 


·         Identify the atoms which undergo a change in the oxidation number in the reaction by assigning the oxidation number to all elements in the reaction.

 

Rounded Rectangle: Step 3 


·         Calculate the increase or decrease in the oxidation number per atom and for the entire molecule or ion in which it occurs.

·         If these are not equal, then multiply by suitable coefficients so that these become equal.

·         If two substances are reduced and nothing is oxidised or vice versa, then something is wrong.

·         Either the oxidation numbers have not been assigned properly or the formulae of reactants or products are wrong.

 

 

 
  Rounded Rectangle: Step 4

 

 

 


·         Ensure the involvement of ions if the reaction is taking place in water.

·         Add H+ or OH ions to the equation on the appropriate side so that the total ionic charges of reactants and products are equal.

·         Use H+ ions in the equation if the reaction is carried out in acidic solution.

·         Use OH ions in the equation if the reaction is carried out in basic solution.

 
  Rounded Rectangle: Step 5

 

 

 


·         In the equation, make the numbers of hydrogen atoms equal by adding water (H2O) molecules to the reactants or products on the two sides.

·         Check the number of oxygen atoms also.

·         If the number of oxygen atoms is the same in the reactants and products, then the equation represents a balanced redox reaction.

          

Example 1:

·         Permanganate ion reacts with bromide ion in the basic medium to give manganese dioxide and bromated ion.

o   Step 1: The skeletal ionic equation is

                    

 

o   Step 2: Assign oxidation numbers for Mn and Br

                 +7                  −1                    +4                 +5  

               

 

This indicates that the permanganate ion is the oxidant and the bromide ion is the reductant.

 

o   Step 3: Calculate the increase and decrease of the oxidation number and make the increase equal to the decrease.

                +7                  −1                     +4                 +5  

             

 

o   Step 4: As the reaction occurs in the basic medium and the ionic charges are not equal on both sides, add 2 OH on the right to make the ionic charges equal.

            

 

o   Step 5: Finally, count the hydrogen atoms and add the appropriate number of water molecules, i.e. one H2O molecule on the left side to achieve a balanced redox change.

          

 

 

Example 2:

·         Reaction of potassium dichromate (VI) (K2Cr2O7) with sodium sulphite (Na2SO3) in an acid solution to give the chromium (III) ion and the sulphate ion.

o   Step 1: The skeletal ionic equation is

                                        

o   Step 2: Assign oxidation numbers for Cr and S

 

         +6 −2          +4 −2              +3            +6 −2

                   

 

This indicates that the dichromate ion is the oxidant and the sulphite ion is the reductant.

o   Step 3: Calculate the increase and decrease of the oxidation number and make them equal.

                              +6 −2          +4 −2                  +3            +6 −2

                                    

 

o   Step 4: As the reaction occurs in the acidic medium and the ionic charges are not equal on both sides, add 8H+ on the left to make ionic charges equal.

 

                                                 

 

o   Step 5: Finally, count the hydrogen atoms and add the appropriate number of water molecules (4H2O) on the right side to achieve the balanced redox reaction.

                                 

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