Two cars of unequal masses use similar tyres if they are moving at the same initial speed the maximum stopping distance? A block placed on a horizontal surface is being pushed by a force F making an angle with the vertical if the coefficient of friction is u how much force is needed to get the block just started?
Asked by tusharpandeyyy
20th August 2018,
8:23 PM
Answered by Expert
Answer:
Only one question per posting is allowed. First question in your posting is very vague. Hence I am answering the second one.
Figure shows the various forces acting on the block of mass m.
In vertical direction :- N + F cosθ = mg or N = mg - F cosθ .................(1)
friction force f = μN = μ(mg-Fcosθ) ......................(2)
to just start to move the block, Horizontal component of the applied force Fsinθ should be equal to the friction force.
hence we have, Fsinθ = μ(mg-Fcosθ) or 
.....................(2)
.....................(2)
Answered by Expert
21st August 2018,
2:44 PM
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