Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/NEET/Magnetic Effect Of Current And Magnetism

the figure is given and at the bottom is its question.

Asked by Arushi Juyal 12th December 2017, 8:34 PM
Answered by Expert
Answer:
Refer the figure for the following calculation.
 
we should find angle α to get the deflected path length in field region
 
begin mathsize 12px style open parentheses R minus h close parentheses squared space plus space fraction numerator m squared v squared over denominator 2 q B space end fraction space equals space R squared space................... left parenthesis 1 right parenthesis R a d i u s space R space i s space o b t a i n e d space f r o m space B q v space equals space fraction numerator m v squared over denominator R end fraction R space equals space fraction numerator m v over denominator B q end fraction B y space s u b s t i t u t i n g space f o r space R space i n space left parenthesis 1 right parenthesis comma space w e space g e t space left parenthesis R minus h right parenthesis space equals fraction numerator m v over denominator square root of 2 q B end fraction end style
Hence α = 45º and deflected path length begin mathsize 12px style equals fraction numerator pi R over denominator 4 end fraction equals space fraction numerator pi m v over denominator 4 q B end fraction end style
It can be seen from figure angle β = α = 45º. Hence begin mathsize 12px style d space equals space fraction numerator m v over denominator q B end fraction end style
Total path length just before collision is begin mathsize 12px style fraction numerator pi m v over denominator 4 q B end fraction plus fraction numerator m v over denominator q B end fraction space equals space fraction numerator m v over denominator 4 q B end fraction open parentheses pi plus 4 close parentheses end style
since the collision is elastic, we will get same path length after collision
 
Hence overall path length is begin mathsize 12px style fraction numerator m v over denominator 2 q B end fraction open parentheses pi plus 4 close parentheses end style
to get time t we divide pathlength by velocity v, then begin mathsize 12px style t space equals space fraction numerator m over denominator 2 q B end fraction open parentheses pi plus 4 close parentheses end style 
Answered by Expert 12th December 2017, 11:08 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Tags: force-on-a-moving-charge magnetic-force
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

Please refer to the uploaded image for the doubt
16th March 2022, 11:08 PM
why magnetic force cannot be contact force
23rd July 2022, 11:34 PM
how to think
16th August 2022, 5:10 PM
question number 8 is my doubt
20th August 2022, 11:17 AM
please explain
25th August 2022, 9:13 AM
RELATED STUDY RESOURCES :
NEET QUESTION ANSWERS

Chat with us on WhatsApp