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 The density of the gas was found to be 3.43 gram per litre at 300 degree Kelvin and one atmosphere. calculate the molar mass when R = 0.0821 litre atmosphere per Kelvin per mole?
 

Asked by hemanttkumarr 13th November 2017, 7:39 AM
Answered by Expert
Answer:
Molar space mass equals dRT over straight P
space space space space space space space space space space space space space space space space equals fraction numerator 3.43 cross times 0.0821 cross times 300 over denominator 1 end fraction
space space space space space space space space space space space space space space space space space equals space 84.48 space straight g divided by mol
Answered by Expert 13th November 2017, 9:55 AM
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