Sir pls solve this question.
Asked by rsudipto
12th December 2018,
9:39 AM
Answered by Expert
Answer:
position for nth bright fringe :- d × sinθ = nλ
position for nth dark fringe :- d × sinθ = [ n - (1/2) ]λ
for 10th bright fringe in liquid : d × sinθ = 10λ/μ ....................(1)
where μ is the refractive index of liquid
for 6th dark fringe in vacuum : d × sinθ = [6-(1/2)]λ ....................(2)
where μ is the refractive index of liquid
Equating (1) and (2), we get, μ = 10/5.5 = 1.82
Answered by Expert
13th December 2018,
9:56 AM
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