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Sir/Ma'am pl tell the above question

Asked by neeraj.unnao 9th August 2017, 4:56 AM
Answered by Expert
Answer:
begin mathsize 16px style integral fraction numerator sin 2 straight x space dx over denominator open parentheses straight a squared plus straight b squared sin squared straight x close parentheses squared end fraction
straight a squared plus straight b squared sin squared straight x equals straight t
straight b squared open parentheses 2 sinxcosx close parentheses dx equals dt
straight b squared sin 2 xdx equals dt................ open square brackets 2 sinxcosx equals sin 2 straight x close square brackets
sin 2 xdx equals fraction numerator begin display style dt end style over denominator straight b squared end fraction
integral fraction numerator fraction numerator begin display style dt end style over denominator straight b squared end fraction over denominator straight t squared end fraction
fraction numerator begin display style 1 end style over denominator straight b squared end fraction integral straight t to the power of negative 2 end exponent dt
fraction numerator begin display style 1 end style over denominator straight b squared end fraction open parentheses fraction numerator straight t to the power of negative 1 end exponent over denominator negative 1 end fraction close parentheses plus straight c
fraction numerator begin display style negative 1 end style over denominator straight b squared end fraction cross times 1 over straight t plus straight c
fraction numerator begin display style negative 1 end style over denominator straight b squared end fraction cross times fraction numerator begin display style 1 end style over denominator begin display style straight a squared plus straight b squared sin squared straight x end style end fraction plus straight c

end style
Answered by Expert 9th August 2017, 9:39 AM
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