sir, ln(tan(90-x)) is writtn as -ln(tanx) and - is removed out of integration and then both the integration are added which makes 2i=0, so i=0

sir, instead of this if we write ln(tan(90-x)) as ln(cot(x)) and then add both the integration an writing ln(tan(x))+ln(cot(x)) as ln(tan(x)*cot(x)) as ln1, so following these steps we get 2i=integration 0, so i=1

is coming from this procedure,

so why both the answers are coming different please explain me or if i am doing something wrong please correct me

Browse free questions and answers by Chapters

• 1 Sequences and Series
• 2 Mathematical Reasoning
• 3 Differential Equations
• 4 Three Dimensional Geometry
• 5 Complex Numbers and Quadratic Equations
• 6 Permutations and Combinations
• 7 Matrices and Determinants
• 8 Vector Algebra
• 9 Trigonometry
• 10 Integral Calculus
• 11 Sets, Relations and Functions
• 12 Limit, Continuity and Differentiability
• 13 Statistics and Probability
• 14 Co-ordinate Geometry
• 15 Mathematical Induction
• 16 Binomial Theorem and its Simple Applications