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Home / Doubts and Solutions/JEE/Mathematics

ques 8

Asked by rbhatt16 12th December 2017, 4:11 PM
Answered by Expert
Answer:
begin mathsize 16px style tan squared straight x. tan squared 3 straight x. tan 4 straight x minus tan 4 straight x equals tan squared straight x minus tan squared 3 straight x tan 4 straight x equals fraction numerator tan squared straight x minus tan cubed straight x over denominator tan squared straight x. tan cubed straight x minus 1 end fraction tan 4 straight x equals fraction numerator open parentheses tanx minus tan 3 straight x close parentheses open parentheses tanx plus tan 3 straight x close parentheses over denominator tan squared straight x. tan squared 3 straight x minus 1 end fraction tan left parenthesis straight x plus 3 straight x right parenthesis equals fraction numerator open parentheses tanx minus tan 3 straight x close parentheses open parentheses tanx plus tan 3 straight x close parentheses over denominator tan squared straight x. tan squared 3 straight x minus 1 end fraction fraction numerator tanx plus tan 3 straight x over denominator 1 minus tanx space tan 3 straight x end fraction equals fraction numerator open parentheses tanx minus tan 3 straight x close parentheses open parentheses tanx plus tan 3 straight x close parentheses over denominator open parentheses tanx. tan 3 straight x minus 1 close parentheses open parentheses tanx. tan 3 straight x plus 1 close parentheses end fraction 1 over 1 equals fraction numerator open parentheses tanx minus tan 3 straight x close parentheses over denominator open parentheses negative 1 close parentheses open parentheses tanx. tan 3 straight x plus 1 close parentheses end fraction minus 1 equals tan left parenthesis straight x minus 3 straight x right parenthesis tan 2 straight x equals 1 tan 2 straight x equals tan straight pi over 4 apply space general space solution space open parentheses nπ plus straight alpha close parentheses end style
Answered by Expert 13th December 2017, 7:38 PM
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