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Home / Doubts and Solutions/JEE/Mathematics

ques 27

Asked by chandanbr6004 10th November 2017, 10:28 PM
Answered by Expert
Answer:
begin mathsize 16px style table row cell open parentheses straight z plus 1 close parentheses to the power of 7 plus straight z to the power of 7 equals 0 end cell row cell open parentheses straight z plus 1 close parentheses to the power of 7 equals negative straight z to the power of 7 end cell row cell straight z plus 1 equals negative straight z end cell row cell straight z equals fraction numerator negative 1 over denominator 2 end fraction end cell end table So space straight z subscript 0 equals straight z subscript 1 equals straight z subscript 2 equals straight z subscript 3 equals straight z subscript 4 equals straight z subscript 5 equals straight z subscript 6 equals fraction numerator negative 1 over denominator 2 end fraction so space sum space is space fraction numerator negative 7 over denominator 2 end fraction end style
Answered by Expert 8th December 2017, 11:57 AM
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