Q) Find the sum of all the numbers greater than 10000 formed by using the digits 1,3, 5, 7, 9 no digit being repeated in any number.
Asked by Anish
29th November 2018,
12:16 PM
Answered by Expert
Answer:
As shown in figure every fixed digit placed at the place of 104 , we can fill the other digit at other places in 24 ways without repeating the digits.
Hence sum of place value of 104 = ( 1+3+5+7+9)×24×104 .........................(1)
Similarly sum of place value of 103 = ( 1+3+5+7+9)×24×103 .......................(2)
Similarly sum of place value of 102 = ( 1+3+5+7+9)×24×102 .......................(3)
Similarly sum of place value of 101 = ( 1+3+5+7+9)×24×101 .......................(4)
Similarly sum of place value of 100 = ( 1+3+5+7+9)×24×100 .......................(5)
If we add all the sum of place values from eqn.(1) to eqn.5), we get 666×104 + 6600
Answered by Expert
3rd December 2018,
6:10 AM
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