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Q)

Asked by araima2001 25th December 2017, 1:41 PM
Answered by Expert
Answer:
begin mathsize 16px style open vertical bar straight Z subscript 1 minus straight Z subscript 2 close vertical bar greater or equal than open vertical bar straight Z subscript 1 close vertical bar minus open vertical bar straight Z subscript 2 close vertical bar
and
open vertical bar straight Z subscript 1 plus straight Z subscript 2 close vertical bar less or equal than open vertical bar straight Z subscript 1 close vertical bar plus open vertical bar straight Z subscript 2 close vertical bar
so space
open vertical bar straight Z subscript 2 minus open parentheses 5 plus 2 square root of 6 straight i close parentheses close vertical bar greater or equal than open vertical bar straight Z subscript 1 close vertical bar minus open vertical bar open parentheses 5 plus 2 square root of 6 straight i close parentheses close vertical bar
3 space greater or equal than open vertical bar straight Z subscript 1 close vertical bar minus 7
10 space greater or equal than open vertical bar straight Z subscript 1 close vertical bar
space so space max space value space of space open vertical bar straight Z subscript 1 close vertical bar equals 10
min space value open vertical bar straight Z subscript 1 close vertical bar equals 0
now space comma open vertical bar straight Z subscript 1 close vertical bar equals 10
open vertical bar straight Z subscript 1 plus straight Z subscript 2 close vertical bar less or equal than 12 plus 10
open vertical bar straight Z subscript 1 plus straight Z subscript 2 close vertical bar less or equal than 22
Now
open vertical bar straight Z subscript 1 plus straight Z subscript 2 close vertical bar equals open vertical bar straight Z subscript 1 minus open parentheses negative straight Z subscript 2 close parentheses close vertical bar
open vertical bar straight Z subscript 1 minus open parentheses negative straight Z subscript 2 close parentheses close vertical bar greater or equal than open vertical bar straight Z subscript 1 close vertical bar minus open vertical bar negative straight Z subscript 2 close vertical bar
open vertical bar straight Z subscript 1 plus straight Z subscript 2 close vertical bar greater or equal than 2
so space
22 greater or equal than space open vertical bar straight Z subscript 1 plus straight Z subscript 2 close vertical bar greater or equal than 2
but space for open vertical bar straight Z subscript 1 minus straight Z subscript 2 close vertical bar and space open vertical bar straight Z subscript 1 close vertical bar equals 10
space open vertical bar straight Z subscript 1 minus straight Z subscript 2 close vertical bar greater or equal than open vertical bar straight Z subscript 1 close vertical bar minus open vertical bar straight Z subscript 2 close vertical bar greater or equal than 12 minus 10 greater or equal than 2
and space for space min space value open vertical bar straight Z subscript 1 close vertical bar equals 0
open vertical bar straight Z subscript 1 minus straight Z subscript 2 close vertical bar greater or equal than open vertical bar straight Z subscript 1 close vertical bar minus open vertical bar straight Z subscript 2 close vertical bar greater or equal than 12
so space no space such space upper space limit
left parenthesis straight d right parenthesis
end style
Answered by Expert 11th January 2018, 1:09 PM
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