[Q.] 12 ( i )
Asked by pukai7229
26th June 2018,
9:39 PM
Answered by Expert
Answer:
cosec²x = 2 cot x
=> 1 + cot²x = 2 cot x
=> cot²x - 2cot x + 1 = 0
=> (cot x - 1)² = 0
=> cot x - 1 = 0
=> cot x = 1 = cot (π/4)
=> x = nπ + π/4
=> 1 + cot²x = 2 cot x
=> cot²x - 2cot x + 1 = 0
=> (cot x - 1)² = 0
=> cot x - 1 = 0
=> cot x = 1 = cot (π/4)
=> x = nπ + π/4
Answered by Expert
29th June 2018,
6:05 PM
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