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Home / Doubts and Solutions/JEE/Mathematics

Plz solve this...?

Asked by dasratna_72 10th May 2017, 9:24 PM
Answered by Expert
Answer:
begin mathsize 16px style straight y equals straight x to the power of open parentheses lnx close parentheses to the power of log open parentheses lnx close parentheses end exponent end exponent Taking space natural space log space on space both space sides comma lny equals ln open parentheses straight x to the power of open parentheses lnx close parentheses to the power of log open parentheses lnx close parentheses end exponent end exponent close parentheses lny equals open parentheses lnx close parentheses to the power of log open parentheses lnx close parentheses end exponent ln open parentheses straight x close parentheses Again space taking space natural space log space on space both space sides comma ln open parentheses lny close parentheses equals ln open parentheses lnx close parentheses to the power of log open parentheses lnx close parentheses end exponent plus ln open parentheses ln open parentheses straight x close parentheses close parentheses ln open parentheses lny close parentheses equals log open parentheses lnx close parentheses ln open parentheses lnx close parentheses plus ln open parentheses ln open parentheses straight x close parentheses close parentheses changing space base space of space the space log comma ln open parentheses lny close parentheses equals fraction numerator ln open parentheses lnx close parentheses over denominator ln 10 end fraction cross times ln open parentheses lnx close parentheses plus ln open parentheses ln open parentheses straight x close parentheses close parentheses ln open parentheses lny close parentheses equals fraction numerator open square brackets ln open parentheses lnx close parentheses close square brackets squared over denominator ln 10 end fraction plus ln open parentheses ln open parentheses straight x close parentheses close parentheses differentiating space on space both space sides comma 1 over ylny dy over dx equals fraction numerator 1 over denominator ln 10 end fraction cross times fraction numerator 2 ln open parentheses lnx close parentheses over denominator xlnx end fraction plus 1 over xlnx dy over dx equals ylny over xlnx open parentheses fraction numerator 2 ln open parentheses lnx close parentheses over denominator ln 10 end fraction plus 1 close parentheses end style
Answered by Expert 11th May 2017, 11:20 AM
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