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Home / Doubts and Solutions/JEE/Mathematics

plz answer it 

Asked by Umesh 1st December 2017, 9:50 AM
Answered by Expert
Answer:
begin mathsize 16px style arg open parentheses fraction numerator straight z minus straight z subscript 1 over denominator straight z minus straight z subscript 2 end fraction close parentheses equals straight pi over 4 arg open parentheses straight z minus straight z subscript 1 close parentheses minus arg open parentheses straight z minus straight z subscript 2 close parentheses equals straight pi over 4 arg open square brackets straight x plus iy minus open parentheses 8 plus 4 straight i close parentheses close square brackets minus arg open square brackets straight x plus iy minus open parentheses 6 plus 4 straight i close parentheses close square brackets equals straight pi over 4 arg left square bracket left parenthesis straight x minus 8 right parenthesis plus straight i left parenthesis straight y minus 4 right parenthesis right square bracket minus arg left square bracket left parenthesis straight x minus 6 right parenthesis plus straight i left parenthesis straight y minus 4 right parenthesis right square bracket equals straight pi over 4 tan to the power of negative 1 end exponent open parentheses fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction close parentheses minus tan to the power of negative 1 end exponent open parentheses fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction close parentheses equals straight pi over 4 tan to the power of negative 1 end exponent open square brackets fraction numerator fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction minus fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction over denominator 1 plus fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction cross times fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction end fraction close square brackets equals straight pi over 4 fraction numerator fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction minus fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction over denominator 1 plus fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction cross times fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction end fraction equals tan straight pi over 4 fraction numerator fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction minus fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction over denominator 1 plus fraction numerator straight y minus 4 over denominator straight x minus 8 end fraction cross times fraction numerator straight y minus 4 over denominator straight x minus 6 end fraction end fraction equals 1 After space simplifying space you space will space get left parenthesis straight x minus 7 right parenthesis squared plus left parenthesis straight y minus 5 right parenthesis squared equals 2 Hence comma space correct space option space is space straight c. end style
Answered by Expert 1st December 2017, 12:01 PM
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