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Home / Doubts and Solutions/JEE/Mathematics

Please solve the attached equation!!

qsnImg
Asked by pukai7229 30th June 2018, 11:18 AM
Answered by Expert
Answer:
begin mathsize 16px style square root of straight x plus 3 end root plus square root of straight x minus 3 end root equals 6 Squaring space on space both space sides comma straight x plus 3 plus straight x minus 3 plus 2 square root of open parentheses straight x plus 3 close parentheses open parentheses straight x minus 3 close parentheses end root equals 36 2 straight x plus 2 square root of open parentheses straight x squared minus 9 close parentheses end root equals 36 straight x plus square root of open parentheses straight x squared minus 9 close parentheses end root equals 18 square root of straight x squared minus 9 end root equals 18 minus straight x Sqauring space on space both space sides comma straight x squared minus 9 equals open parentheses 18 minus straight x close parentheses squared straight x squared minus 9 equals 324 minus 36 straight x plus straight x squared 36 straight x equals 333 straight x equals 333 over 36 straight x equals 111 over 18 end style
Answered by Expert 6th July 2018, 10:15 AM
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