Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Please answer the following question with explanation

qsnImg
Asked by Deepak 8th September 2018, 8:07 PM
Answered by Expert
Answer:

Given:

 
straight E subscript straight a subscript 1 minus space end subscript straight E subscript straight a subscript 2 end subscript equals space 2000 space cal 2000 cal
 
 
T2 = 27 °C
 
    = 300 K
 
Arrhenius equation is,
 
straight k space equals space Ae to the power of bevelled fraction numerator open parentheses negative straight E subscript straight a close parentheses over denominator RT end fraction end exponent

straight k subscript 2 over straight k subscript 1 space equals space straight e to the power of bevelled fraction numerator open parentheses straight E subscript straight a subscript 2 end subscript minus straight E subscript straight a subscript 1 end subscript close parentheses over denominator RT end fraction end exponent

space space space space space space equals space straight e to the power of open parentheses bevelled fraction numerator 2000 over denominator 1.9872 cross times 300 end fraction close parentheses end exponent

straight k subscript 2 over straight k subscript 1 space space equals straight e to the power of 3.35 end exponent

Taking space log space on space both space the space sides comma

log straight k subscript 2 over straight k subscript 1 equals fraction numerator 3.35 over denominator 2.303 end fraction

log straight k subscript 2 over straight k subscript 1 space equals 1.4567

Taking space antilog

straight k subscript 2 over straight k subscript 1 space equals space antilog open parentheses 1.4567 close parentheses

straight k subscript 2 over straight k subscript 1 space equals space 28.1

straight k subscript 2 over straight k subscript 1 space almost equal to 28
Therefore the rate of reaction will be 28 times.
Answered by Expert 10th September 2018, 12:16 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

8th April 2024, 6:42 AM

Chat with us on WhatsApp