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Home / Doubts and Solutions/JEE/Mathematics

kindly provide solution

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Asked by arup.isro 7th June 2018, 11:53 PM
Answered by Expert
Answer:
begin mathsize 16px style straight y equals fraction numerator straight x squared plus 2 straight x plus straight c over denominator straight x squared plus 4 straight x plus 3 straight c end fraction straight y greater than 0 space if space and space only space if space straight x squared plus 4 straight x plus 3 straight c not equal to 0 Let space us space consider space straight x squared plus 4 straight x plus 3 straight c space equals space 0 straight x space equals space fraction numerator negative 4 plus-or-minus 2 square root of 4 minus 3 straight c end root over denominator 2 end fraction 4 minus 3 straight c greater than 0 straight c less than 4 over 3 Hence comma space correct space option space is space straight A. end style
Answered by Expert 8th June 2018, 11:23 AM
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