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instantaneous velocity of a body of mass 5kg is given v=(3tcube+2tsquare+25m/s)calculate the force experienced by the body at t=3sec

 

Asked by puneetgarg2555 15th June 2018, 7:27 PM
Answered by Expert
Answer:
velocity v(t) as a function of time is given as

begin mathsize 12px style v left parenthesis t right parenthesis space equals space 3 t cubed space plus space 2 t squared space plus 25
a c c e l e r a t i o n space fraction numerator d v over denominator d t end fraction equals 9 t squared plus 4 t
a c c e l e r a t i o n space a t space t equals 3 space s comma space space right enclose fraction numerator d v over denominator d t end fraction end enclose subscript space t equals 3 end subscript space equals space 9 cross times 9 plus 4 cross times 3 space equals space 93 space m divided by s squared space
f o r c e space equals space m a s s space cross times space a c c e l e r a t i o n space equals space 5 cross times 93 space equals space 465 space N end style
Answered by Expert 15th June 2018, 10:21 PM
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