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# In a battle 70%of the combatants lost one eye , 80%an ear, 75%an arm, 85% a leg, x%lost all four limbs. The min value of x is?

Asked by pks441006 11th December 2018, 1:55 PM
Let A - lost eye
B - lost ear
C - lost arm
D - lost leg
Find n(A ∩ B) = n(A) + n(B) - 100%
n(A ∩ B) = 70% + 80% - 100%
n(A ∩ B) = 50%

Also find n(B ∩ C) and n(C ∩ D), n(A ∩ D)
Then use
n(A υ B υ C υ D) = n(A) + n(B) + n(C) + n(D) - n(A ∩ B) - n(B ∩ C) - n(C ∩ D) - n(A ∩ D) + n(A ∩ B ∩ C ∩ D)
to find required answer.
Answered by Expert 11th December 2018, 5:53 PM
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Tags: probability