(i) Draw the graph of f: {-2,-1,0,1,2} ? R by f(x) = x3
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15th February 2012,
4:05 PM
Answered by Expert
Answer:
when x= -2 -1 0 1 2
y= f(x)= -8 -1 0 1 8
plot these poin ts against x and y on the axis,as a smooth curve
It will pass trough origin .
Yes it is a real valued func for all real values of x
Answered by Expert
17th February 2012,
10:08 AM
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