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How many elements would be in the IInd period of the Periodic Table if the spin quanturm numbers could have the value +1/2,0,−1/2?

 

Solution

For IInd period 
n=2 hence

I m s
0 0 +12,0,−12
1 −1 +12,0,−12
  0 +12,0,−12
  +1 +12,0,−12
   answer is 12. Please explain me the solution

Asked by imtiyazmulla68 26th April 2018, 11:11 AM
Answered by Expert
Answer:

In the modern periodic table, the second period has a principal quantum number is 2

And there are 2s and 2p orbitals are in 2nd period which is going to be filled.

As given that there are 3 spin quantum numbers(-1/2, 0, +1/2) for each suborbital hence 3 electrons will be there in each suborbital.

The total number of sub-orbitals of s and p (px, py, pz) are 1 and 3 respectively

 

Maximum electrons in orbital= spin quantum no.(s)  X azimuthal quantum no.(l)

As given s= 3 and for s orbital l = 1

Maximum electrons in s orbital = 3 X 1 = 3

 

For p orbital, I = 3 and as given s= 3

Maximum electrons in p orbital = 3 X 3 = 9

 

Thus there will be 3 + 9 = 12 elements in the 2nd period of the periodic table.

Answered by Expert 3rd May 2018, 11:44 AM
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