how can i solve this ??
Asked by pukai7229
15th May 2018,
10:23 AM
Answered by Expert
Answer:
Component of applied force in the direction of motion of toy trains, F = 1.5×cos 30º = 1.5×(√3/2) = 1.3 N;
acceleration = force/mass = 1.3/(60×10-3) = 21.67 m/s2
acceleration is same for both toys.
Tension in the string pulling the toy of mass 20g. Hence Tension in the string = 20×10-3×21.67 = 0.433 N
Answered by Expert
15th May 2018,
3:01 PM
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