Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Find value of imax -imin /imax+imin

 

qsnImg
Asked by tandonyashika 3rd November 2018, 8:03 PM
Answered by Expert
Answer:
When two coherent sources of intensities I1 and I2 are combined,
we get the maximum Imax  and minimum Imin intensities are given by
 
begin mathsize 12px style I subscript m a x end subscript equals space I subscript 1 space plus space I subscript 2 space plus space 2 square root of I subscript 1 I subscript 2 end root space.................. space left parenthesis 1 right parenthesis
I subscript m i n end subscript space equals space I subscript 1 space plus space I subscript 2 space minus space 2 square root of I subscript 1 I subscript 2 end root space space.................. left parenthesis 2 right parenthesis end style
 
begin mathsize 12px style fraction numerator I subscript m a x end subscript minus space I subscript m i n end subscript over denominator I subscript m a x end subscript plus space I subscript m i n end subscript end fraction space equals space fraction numerator begin display style 2 end style square root of I subscript 1 I subscript 2 end root over denominator open parentheses I subscript 1 plus I subscript 2 close parentheses end fraction space space................... left parenthesis 3 right parenthesis end style
It is given that two intensities are in the ratio β, hence we assume I2 = β×I1 ....................(4)
 
By substituting I2 from eqn.(4) in eqn.(3), we get
 
begin mathsize 12px style fraction numerator I subscript m a x end subscript minus space I subscript m i n end subscript over denominator I subscript m a x end subscript plus space I subscript m i n end subscript end fraction space equals space fraction numerator 2 square root of beta over denominator 1 plus beta end fraction space space space end style
Answered by Expert 4th November 2018, 9:23 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Tags: intensity
Your answer has been posted successfully!

Chat with us on WhatsApp