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Find the equation of a line perpendicular to the line x-2y+3=0 and passing through the point(1,-2). 
 
[I can't exatly understand the substitution for Y-Y1=m(X-X1).]

Asked by Deebu 2nd February 2015, 9:00 PM
Answered by Expert
Answer:
G i v e n space e q u a t i o n space o f space t h e space l i n e space i s space x minus 2 y plus 3 equals 0 rightwards double arrow x plus 3 equals 2 y rightwards double arrow y equals fraction numerator x plus 3 over denominator 2 end fraction rightwards double arrow y equals x over 2 plus 3 over 2 S l o p e space o f space t h e space g i v e n space l i n e space i s space m equals 1 half S l o p e space o f space t h e space l i n e space p e r p e n d i c u l a r space t o space t h e space g i v e n space l i n e space equals fraction numerator negative 1 over denominator 1 half end fraction equals negative 2 A l s o space g i v e n space t h a t space t h e space r e q u i r e d space l i n e space p a s s e s space t h r o u g h space t h e space p o i n t space open parentheses 1 comma negative 2 close parentheses  T h e space e q u a t i o n space o f space t h e space l i n e space w i t h space t h e space s l o p e space m space a n d space p a s s e s space t h r o u g h space t h e space p o i n t space open parentheses x subscript 1 comma y subscript 1 close parentheses space i s y minus y subscript 1 equals m open parentheses x minus x subscript 1 close parentheses T h u s space t h e space r e q u i r e d space e q u a t i o ln space i s y minus open parentheses negative 2 close parentheses equals negative 2 open parentheses x minus 1 close parentheses rightwards double arrow y plus 2 equals negative 2 x plus 2 rightwards double arrow 2 x plus y equals 0
Answered by Expert 2nd February 2015, 9:50 PM
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