Please wait...
Contact Us
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry



Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9372462318 / 9987178554

Mon to Sat - 10 AM to 7 PM

explain the answer 

Asked by Arushi Juyal 16th December 2017, 6:38 AM
Answered by Expert
Vector OQ is drawn at O and parallel to Velocity vector v at P. If vector OQ makes an angle β with horizontal which is 90-α, then it can be seen from the figure that velocity vector v makes same angle β with the horizontal component. In projectile motion horizontal component of the velocity remains constant.
Hence v cos β = v cos (90-α) = v sin α = u cos α ;   hence v = u cot α
Answered by Expert 18th December 2017, 12:43 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp