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Detailed solution for this.

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Asked by g_archanasharma 16th December 2018, 6:11 PM
Answered by Expert
Answer:
Given series :  log3 2 , log6 2 , log12
 
Reciprocals of respective term in given series : log2 3 , log2 6 , log2 12
 
Sum of first and third term of above series  = log2 3 + log2 12 = log2 36 = 2 log2 6
Hence middle term is average of first and third term and the series is in A.P.
 
Since reciprocals of respective terms of given series are in A.P, Given series is in H.P
Answered by Expert 16th December 2018, 11:24 PM
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