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define simple harmonic motion. derive an expression for the potential energy and K.E of a harmonic oscillator. hence show that total energy remains conserved in S.H.M

Asked by futureisbright051101 5th March 2018, 7:30 PM
Answered by Expert
Answer:
If an object is under oscillating motion and at any instant the force acting on it is proportional to its displacement from equilibrium position, then such an oscillating motion is called Simple harmonic motion (SHM).
Mathematically F(x) = -k×x....................(1)
where k is constant and negative sign indicates direction of force and direction of displacement are opposite.
 
Equation (1) can be rewritten by using the definition of force = mass times acceleration
begin mathsize 12px style negative k space x space equals space m fraction numerator d squared x over denominator d t squared end fraction space semicolon space h e n c e space fraction numerator d squared x over denominator d t squared end fraction plus k over m x space equals space 0 semicolon T h i s space d i f f e r e n t i a l space e q u a t i o n space h a s space s o l u t i o n space colon space x space equals space x subscript m cos left parenthesis omega t plus ϕ right parenthesis space............ left parenthesis 2 right parenthesis end style
 
where x is displacement, xm is amplitude of SHM, ω is angular frequency;  
ω= 2πf  where f is the frequency of oscillation and Φ is phase constant.
 
begin mathsize 12px style v e l o c i t y space o f space a n space o b j e c t space u n d e r space S H M space i s space fraction numerator d x over denominator d t end fraction equals space v subscript x space equals negative omega x subscript m sin open parentheses omega t plus ϕ close parentheses space................ left parenthesis 3 right parenthesis p o t e n t i a l space e n e r g y space U space equals 1 half k x squared space equals space 1 half space k space x subscript m superscript 2 space cos squared open parentheses omega t plus ϕ close parentheses space.............. left parenthesis 4 right parenthesis K i n e t i c space e n e r g y space K space equals space 1 half m v subscript x superscript 2 space equals space 1 half m omega squared x subscript m superscript 2 sin squared open parentheses omega t plus ϕ close parentheses............... left parenthesis 5 right parenthesis u sin g space left parenthesis 4 right parenthesis space a n d space left parenthesis 5 right parenthesis space w e space w r i t e space t o t a l space e n e r g y space K plus U space equals space 1 half k space x subscript m superscript 2 space space left parenthesis space w e space u s e d space t h e space r e l a t i o n space omega space equals square root of k over m end root space right parenthesis end style
hence total energy is constant
Answered by Expert 6th March 2018, 10:22 AM
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