Calculate the pH of .0678 M NaOH.
Asked by निकोदिमुस
12th September 2017,
7:49 PM
Answered by Expert
Answer:
pOH of 0.678 M NaOH = -log10(0.678) = -(-0.17) = 0.17
pH = 10 - 0.17
pH = 9.83
Answered by Expert
13th September 2017,
7:30 PM
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