calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.40 .
Asked by निकोदिमुस
4th October 2017,
6:26 PM
Answered by Expert
Answer:
Moles of ethanol = 0.04 mol
Moles of water = 1 - 0.04 = 0.96 mol
Mass of ethanol = 0.04 mol x 46 g/mol = 1.84 g
Mass of water = 0.96 mol x 18 g/mol = 17.3 g
Mass of the solution = 17.3 g + 1.84 g = 19.1g
Assuming density of water to be 1 g/ml,
Volume of solution = mass / density = 19.1 / 1 = 19.1 ml = 0.0191 L
Molarity is the number of moles of solute present in 1 L of solution.
Hence,
Molarity of the solution = 0.040 / 0.0191 = 2.1 M
Answered by Expert
5th October 2017,
10:08 AM
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